#115287: "had to fight bandit twice"
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| # | Status | Votes | Game | Type | Title | Last update |
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细节描述
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• 如果有的话，请将你在屏幕上所看到的错误信息粘贴出来.
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
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• 请说明你当时想做什么，你做了什么，然后发生了什么
at the end of the game when it killed us
• 您正使用哪一款浏览器呢？
Google Chrome v121
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• 请简明而精确地解释您的建议，以便让人明白您想表达的意思。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 您正使用哪一款浏览器呢？
Google Chrome v121
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• 当你被封锁的时候，屏幕上出现了些什么呢？(空白的屏幕？部分游戏平台画面？错误的信息？)
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 您正使用哪一款浏览器呢？
Google Chrome v121
-
• 哪个规则没有被BGA的设计小组写进游戏里？
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
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• 在游戏回放中，是否有不符合游戏规则的地方？如果有的话，请问是在哪一步呢？
at the end of the game when it killed us
• 您正使用哪一款浏览器呢？
Google Chrome v121
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• 你当时是想做哪个游戏行动？
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
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• 你在想做什么的时候，触发了这个游戏选项？
at the end of the game when it killed us
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• 当你想这么做时，发生了什么事(错误信息，游戏状态信息，......)？
• 您正使用哪一款浏览器呢？
Google Chrome v121
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• 请问这个问题发生在游戏的哪个阶段(当前的游戏说明是什么)？
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
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• 当你想进行一个游戏行动时，发生了什么事(错误信息，游戏状态信息，......)？
at the end of the game when it killed us
• 您正使用哪一款浏览器呢？
Google Chrome v121
-
• 请描述一下显示画面上面的问题。 如果你有这个系统漏洞发生时的屏幕截图(画质不要太差)，你可以使用Imgur.com来把它上传到网络，然后将链接复制/粘贴到这里来。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 您正使用哪一款浏览器呢？
Google Chrome v121
-
• 请简明而精确地解释您的建议，以便让人明白您想表达的意思。
after defeating the bandit, when 2 players were on same bandit, had to fight bandit a second time.
• 您正使用哪一款浏览器呢？
Google Chrome v121
案件历史
Move 89: Clutron started the Bandit card
Move 90: Clutron decided to attack the Bandit rather than bribe him
...
Move 97: Bandit is defeated
[At this point, Clutron's turn is done, but runescience hasn't encountered a card yet]
Move 98: runescience starts the Bandit card
Move 99: runescience also decided not to bribe the Bandit.
I'm not sure there's a bug here.
Both players need to encounter all non-monster cards and the bandit is not a monster. If a monster results from an encounter, both players will fight the monster together, but it doesn't end the encounter for the player who hasn't gone yet.
For example, the rules are explicit that both players encounter a trap. Whether the first player succeeds or fails, the second player will also encounter the same trap. Even if the first player rolls the dungeon die such that they fight a monster, the other player must still encounter the trap and may roll that same monster die again.
It works this way for all non-monster cards. The Bandit isn't a monster card; it's a different sort of encounter where a decision is made. You both made decisions that resulted in combats.
From the rules, you got no mention of the bandit, so:
- if you consider the bandit is not a monster, then you got no indication of what you should do with it. Since it's not writed on the rules, I don't see why you couldn't just ignore the bandit on that case? It's a card without effect (I'm trolling here, but that's my main point)
- if you consider the bandit is a monster, then the rules makes sense to me, and so "It is a fight to the death, and whoever loses all their HP dies horribly", so the bandit dies. So I would assume that bandit is discarded or has no effect anymore
From the forum post, it's a question about what if one player pay the toll and the other one don't. It's not what is present here (or on that game: boardgamearena.com/archive/replay/240320-1000/?table=496542833&player=84207926&comments=84207926;# floor 3 i think ).
So what I would propose is the following:
- first player can choose to pay the toll or not:
if he does not goes to fight section
if he does, then the second player can choose to pay the toll or not. If he does not, goes to fight section. If he does, end the event for both players
Fight section: disable the toll option, and make everyone restart the card they are on. Which mean anyone can choose who will fight the bandit first. Once he is defeated end the card.
I don't think you should ever have two fights on a row from a single bandit card.
> if you consider the bandit is not a monster, then
> you got no indication of what you should do with it
This is untrue. The rules definitely cover how non-monsters are encountered by two players. Both player must encounter all non-monster cards separately. For example, traps are encountered by both players separately, even if the trap results in both players needing to face a monster. Bandit works like that, too.
Then it's double monster, which makes it a very horrible card.
It makes no sense to me...
As I'm not interested in debating this, I'll kindly refer you to the forums if you wish to discuss it further, especially since this report is already a dupliciate of another false report.
增加一些新内容到这篇报告
- 其他的游戏桌 ID / 移动 ID
- 按 F5 是否解决了这个问题？
- 问题是否发生了好几次？还是每次都发生？还是时好时坏？
- 如果你有这个系统漏洞发生时的屏幕截图(画质不要太差)，你可以使用Imgur.com来把它上传到网络，然后将链接复制/粘贴到这里来。
